Base | Representation |
---|---|
bin | 111010000110011110101110… |
… | …011000111100011100111011 |
3 | 1020111202121202210021011111112 |
4 | 322012132232120330130323 |
5 | 231443114021243101141 |
6 | 2303245441005550535 |
7 | 104552402204103563 |
oct | 7206365630743473 |
9 | 1214677683234445 |
10 | 255532005050171 |
11 | 74469573166283 |
12 | 247ab99357544b |
13 | ac777457b0b95 |
14 | 4715b5a653da3 |
15 | 1e81e91bdb7eb |
hex | e867ae63c73b |
255532005050171 has 2 divisors, whose sum is σ = 255532005050172. Its totient is φ = 255532005050170.
The previous prime is 255532005050159. The next prime is 255532005050213. The reversal of 255532005050171 is 171050500235552.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255532005050171 - 210 = 255532005049147 is a prime.
It is not a weakly prime, because it can be changed into another prime (255532005050471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127766002525085 + 127766002525086.
It is an arithmetic number, because the mean of its divisors is an integer number (127766002525086).
Almost surely, 2255532005050171 is an apocalyptic number.
255532005050171 is a deficient number, since it is larger than the sum of its proper divisors (1).
255532005050171 is an equidigital number, since it uses as much as digits as its factorization.
255532005050171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 262500, while the sum is 41.
The spelling of 255532005050171 in words is "two hundred fifty-five trillion, five hundred thirty-two billion, five million, fifty thousand, one hundred seventy-one".
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