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255545120435113 is a prime number
BaseRepresentation
bin111010000110101010111100…
…001000001010101110101001
31020111210212121211011202100101
4322012222330020022232221
5231443322401312410423
62303255450242105401
7104553345211041505
oct7206527410125651
91214725554152311
10255545120435113
1174474093490093
12247b243394b261
13ac78a55a51ca2
144716642457305
151e824ad3317ad
hexe86abc20aba9

255545120435113 has 2 divisors, whose sum is σ = 255545120435114. Its totient is φ = 255545120435112.

The previous prime is 255545120435069. The next prime is 255545120435161. The reversal of 255545120435113 is 311534021545552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 254103110934544 + 1442009500569 = 15940612^2 + 1200837^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255545120435113 is a prime.

It is not a weakly prime, because it can be changed into another prime (255545120415113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127772560217556 + 127772560217557.

It is an arithmetic number, because the mean of its divisors is an integer number (127772560217557).

Almost surely, 2255545120435113 is an apocalyptic number.

It is an amenable number.

255545120435113 is a deficient number, since it is larger than the sum of its proper divisors (1).

255545120435113 is an equidigital number, since it uses as much as digits as its factorization.

255545120435113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800000, while the sum is 46.

The spelling of 255545120435113 in words is "two hundred fifty-five trillion, five hundred forty-five billion, one hundred twenty million, four hundred thirty-five thousand, one hundred thirteen".