Base | Representation |
---|---|
bin | 100101001011111100110… |
… | …101000001110101111001 |
3 | 100001022001212101222012202 |
4 | 211023330311001311321 |
5 | 313332031244132213 |
6 | 5233543020115545 |
7 | 352424330303126 |
oct | 45137465016571 |
9 | 10038055358182 |
10 | 2555452333433 |
11 | 8a584124911a |
12 | 35331b995bb5 |
13 | 156c93c1655c |
14 | 8b9825ad74d |
15 | 46716eabb58 |
hex | 252fcd41d79 |
2555452333433 has 2 divisors, whose sum is σ = 2555452333434. Its totient is φ = 2555452333432.
The previous prime is 2555452333429. The next prime is 2555452333453. The reversal of 2555452333433 is 3343332545552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2058269400889 + 497182932544 = 1434667^2 + 705112^2 .
It is a cyclic number.
It is not a de Polignac number, because 2555452333433 - 22 = 2555452333429 is a prime.
It is not a weakly prime, because it can be changed into another prime (2555452333453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277726166716 + 1277726166717.
It is an arithmetic number, because the mean of its divisors is an integer number (1277726166717).
Almost surely, 22555452333433 is an apocalyptic number.
It is an amenable number.
2555452333433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2555452333433 is an equidigital number, since it uses as much as digits as its factorization.
2555452333433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9720000, while the sum is 47.
Adding to 2555452333433 its reverse (3343332545552), we get a palindrome (5898784878985).
The spelling of 2555452333433 in words is "two trillion, five hundred fifty-five billion, four hundred fifty-two million, three hundred thirty-three thousand, four hundred thirty-three".
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