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2555452333433 is a prime number
BaseRepresentation
bin100101001011111100110…
…101000001110101111001
3100001022001212101222012202
4211023330311001311321
5313332031244132213
65233543020115545
7352424330303126
oct45137465016571
910038055358182
102555452333433
118a584124911a
1235331b995bb5
13156c93c1655c
148b9825ad74d
1546716eabb58
hex252fcd41d79

2555452333433 has 2 divisors, whose sum is σ = 2555452333434. Its totient is φ = 2555452333432.

The previous prime is 2555452333429. The next prime is 2555452333453. The reversal of 2555452333433 is 3343332545552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2058269400889 + 497182932544 = 1434667^2 + 705112^2 .

It is a cyclic number.

It is not a de Polignac number, because 2555452333433 - 22 = 2555452333429 is a prime.

It is not a weakly prime, because it can be changed into another prime (2555452333453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277726166716 + 1277726166717.

It is an arithmetic number, because the mean of its divisors is an integer number (1277726166717).

Almost surely, 22555452333433 is an apocalyptic number.

It is an amenable number.

2555452333433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2555452333433 is an equidigital number, since it uses as much as digits as its factorization.

2555452333433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9720000, while the sum is 47.

Adding to 2555452333433 its reverse (3343332545552), we get a palindrome (5898784878985).

The spelling of 2555452333433 in words is "two trillion, five hundred fifty-five billion, four hundred fifty-two million, three hundred thirty-three thousand, four hundred thirty-three".