Base | Representation |
---|---|
bin | 1011100111110000100010… |
… | …10000101000100000011001 |
3 | 10100111001210221010211200222 |
4 | 11303320101100220200121 |
5 | 11322144321303442324 |
6 | 130203544033005425 |
7 | 5245212162200234 |
oct | 563702120504031 |
9 | 110431727124628 |
10 | 25555344984089 |
11 | 8162a63020768 |
12 | 2a489693b3875 |
13 | 1134b2171245b |
14 | 644c5737c41b |
15 | 2e4b46e2e55e |
hex | 173e11428819 |
25555344984089 has 2 divisors, whose sum is σ = 25555344984090. Its totient is φ = 25555344984088.
The previous prime is 25555344984031. The next prime is 25555344984101. The reversal of 25555344984089 is 98048944355552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17634120490000 + 7921224494089 = 4199300^2 + 2814467^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25555344984089 is a prime.
It is not a weakly prime, because it can be changed into another prime (25555344984889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12777672492044 + 12777672492045.
It is an arithmetic number, because the mean of its divisors is an integer number (12777672492045).
Almost surely, 225555344984089 is an apocalyptic number.
It is an amenable number.
25555344984089 is a deficient number, since it is larger than the sum of its proper divisors (1).
25555344984089 is an equidigital number, since it uses as much as digits as its factorization.
25555344984089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160000, while the sum is 71.
The spelling of 25555344984089 in words is "twenty-five trillion, five hundred fifty-five billion, three hundred forty-four million, nine hundred eighty-four thousand, eighty-nine".
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