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25555344984089 is a prime number
BaseRepresentation
bin1011100111110000100010…
…10000101000100000011001
310100111001210221010211200222
411303320101100220200121
511322144321303442324
6130203544033005425
75245212162200234
oct563702120504031
9110431727124628
1025555344984089
118162a63020768
122a489693b3875
131134b2171245b
14644c5737c41b
152e4b46e2e55e
hex173e11428819

25555344984089 has 2 divisors, whose sum is σ = 25555344984090. Its totient is φ = 25555344984088.

The previous prime is 25555344984031. The next prime is 25555344984101. The reversal of 25555344984089 is 98048944355552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17634120490000 + 7921224494089 = 4199300^2 + 2814467^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25555344984089 is a prime.

It is not a weakly prime, because it can be changed into another prime (25555344984889) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12777672492044 + 12777672492045.

It is an arithmetic number, because the mean of its divisors is an integer number (12777672492045).

Almost surely, 225555344984089 is an apocalyptic number.

It is an amenable number.

25555344984089 is a deficient number, since it is larger than the sum of its proper divisors (1).

25555344984089 is an equidigital number, since it uses as much as digits as its factorization.

25555344984089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160000, while the sum is 71.

The spelling of 25555344984089 in words is "twenty-five trillion, five hundred fifty-five billion, three hundred forty-four million, nine hundred eighty-four thousand, eighty-nine".