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25555344984031 is a prime number
BaseRepresentation
bin1011100111110000100010…
…10000101000011111011111
310100111001210221010211121211
411303320101100220133133
511322144321303442111
6130203544033005251
75245212162200122
oct563702120503737
9110431727124554
1025555344984031
118162a63020715
122a489693b3827
131134b21712415
14644c5737c3b9
152e4b46e2e521
hex173e114287df

25555344984031 has 2 divisors, whose sum is σ = 25555344984032. Its totient is φ = 25555344984030.

The previous prime is 25555344984023. The next prime is 25555344984089. The reversal of 25555344984031 is 13048944355552.

It is an a-pointer prime, because the next prime (25555344984089) can be obtained adding 25555344984031 to its sum of digits (58).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25555344984031 - 23 = 25555344984023 is a prime.

It is a super-2 number, since 2×255553449840312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25555344984431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12777672492015 + 12777672492016.

It is an arithmetic number, because the mean of its divisors is an integer number (12777672492016).

Almost surely, 225555344984031 is an apocalyptic number.

25555344984031 is a deficient number, since it is larger than the sum of its proper divisors (1).

25555344984031 is an equidigital number, since it uses as much as digits as its factorization.

25555344984031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840000, while the sum is 58.

The spelling of 25555344984031 in words is "twenty-five trillion, five hundred fifty-five billion, three hundred forty-four million, nine hundred eighty-four thousand, thirty-one".