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2556450103 = 23497108799
BaseRepresentation
bin1001100001100000…
…0101010100110111
320121011102010021011
42120120011110313
520213422400403
61101401333051
7120231316204
oct23030052467
96534363234
102556450103
1110a205a889
125b4197187
1331983568c
141a3746cab
15ee67ba6d
hex98605537

2556450103 has 4 divisors (see below), whose sum is σ = 2556582400. Its totient is φ = 2556317808.

The previous prime is 2556450097. The next prime is 2556450107. The reversal of 2556450103 is 3010546552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2556450103 - 29 = 2556449591 is a prime.

It is a super-3 number, since 3×25564501033 (a number of 29 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2556450107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30903 + ... + 77896.

It is an arithmetic number, because the mean of its divisors is an integer number (639145600).

Almost surely, 22556450103 is an apocalyptic number.

2556450103 is a deficient number, since it is larger than the sum of its proper divisors (132297).

2556450103 is a wasteful number, since it uses less digits than its factorization.

2556450103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132296.

The product of its (nonzero) digits is 18000, while the sum is 31.

The square root of 2556450103 is about 50561.3498929766. The cubic root of 2556450103 is about 1367.3481483341.

Adding to 2556450103 its reverse (3010546552), we get a palindrome (5566996655).

The spelling of 2556450103 in words is "two billion, five hundred fifty-six million, four hundred fifty thousand, one hundred three".

Divisors: 1 23497 108799 2556450103