Base | Representation |
---|---|
bin | 1110111000011010111… |
… | …0010000100110001011 |
3 | 220102220121200112121011 |
4 | 3232012232100212023 |
5 | 13142044304002021 |
6 | 313241120424351 |
7 | 24320401365535 |
oct | 3560656204613 |
9 | 812817615534 |
10 | 255663344011 |
11 | 99476324449 |
12 | 416711780b7 |
13 | 1b15549441a |
14 | c534a28855 |
15 | 69b5101de1 |
hex | 3b86b9098b |
255663344011 has 2 divisors, whose sum is σ = 255663344012. Its totient is φ = 255663344010.
The previous prime is 255663343973. The next prime is 255663344023. The reversal of 255663344011 is 110443366552.
255663344011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255663344011 - 225 = 255629789579 is a prime.
It is a super-3 number, since 3×2556633440113 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (255663344081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127831672005 + 127831672006.
It is an arithmetic number, because the mean of its divisors is an integer number (127831672006).
Almost surely, 2255663344011 is an apocalyptic number.
255663344011 is a deficient number, since it is larger than the sum of its proper divisors (1).
255663344011 is an equidigital number, since it uses as much as digits as its factorization.
255663344011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 255663344011 in words is "two hundred fifty-five billion, six hundred sixty-three million, three hundred forty-four thousand, eleven".
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