Base | Representation |
---|---|
bin | 1110111000011010111… |
… | …0010000100110010111 |
3 | 220102220121200112121121 |
4 | 3232012232100212113 |
5 | 13142044304002043 |
6 | 313241120424411 |
7 | 24320401365553 |
oct | 3560656204627 |
9 | 812817615547 |
10 | 255663344023 |
11 | 9947632445a |
12 | 41671178107 |
13 | 1b155494429 |
14 | c534a28863 |
15 | 69b5101ded |
hex | 3b86b90997 |
255663344023 has 2 divisors, whose sum is σ = 255663344024. Its totient is φ = 255663344022.
The previous prime is 255663344011. The next prime is 255663344081. The reversal of 255663344023 is 320443366552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255663344023 - 213 = 255663335831 is a prime.
It is a super-3 number, since 3×2556633440233 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255663344423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127831672011 + 127831672012.
It is an arithmetic number, because the mean of its divisors is an integer number (127831672012).
Almost surely, 2255663344023 is an apocalyptic number.
255663344023 is a deficient number, since it is larger than the sum of its proper divisors (1).
255663344023 is an equidigital number, since it uses as much as digits as its factorization.
255663344023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 43.
The spelling of 255663344023 in words is "two hundred fifty-five billion, six hundred sixty-three million, three hundred forty-four thousand, twenty-three".
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