Base | Representation |
---|---|
bin | 1110111000011100110… |
… | …0111111001000100111 |
3 | 220102221011211202220021 |
4 | 3232013030333020213 |
5 | 13142103334231301 |
6 | 313242005220011 |
7 | 24320530014403 |
oct | 3560714771047 |
9 | 812834752807 |
10 | 255671398951 |
11 | 9947a926221 |
12 | 41673a01607 |
13 | 1b157054867 |
14 | c535b24103 |
15 | 69b5b938a1 |
hex | 3b8733f227 |
255671398951 has 2 divisors, whose sum is σ = 255671398952. Its totient is φ = 255671398950.
The previous prime is 255671398909. The next prime is 255671398991. The reversal of 255671398951 is 159893176552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255671398951 - 29 = 255671398439 is a prime.
It is a super-2 number, since 2×2556713989512 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 255671398951.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255671398991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127835699475 + 127835699476.
It is an arithmetic number, because the mean of its divisors is an integer number (127835699476).
Almost surely, 2255671398951 is an apocalyptic number.
255671398951 is a deficient number, since it is larger than the sum of its proper divisors (1).
255671398951 is an equidigital number, since it uses as much as digits as its factorization.
255671398951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20412000, while the sum is 61.
The spelling of 255671398951 in words is "two hundred fifty-five billion, six hundred seventy-one million, three hundred ninety-eight thousand, nine hundred fifty-one".
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