Base | Representation |
---|---|
bin | 1110111000011110010… |
… | …1001110101100010011 |
3 | 220102221121210122120022 |
4 | 3232013211032230103 |
5 | 13142112001113011 |
6 | 313242353334055 |
7 | 24320635023542 |
oct | 3560745165423 |
9 | 812847718508 |
10 | 255677754131 |
11 | 99483476a38 |
12 | 41675b6732b |
13 | 1b15846b417 |
14 | c5368da159 |
15 | 69b64eb8db |
hex | 3b8794eb13 |
255677754131 has 2 divisors, whose sum is σ = 255677754132. Its totient is φ = 255677754130.
The previous prime is 255677754077. The next prime is 255677754133. The reversal of 255677754131 is 131457776552.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255677754131 is a prime.
It is a super-2 number, since 2×2556777541312 (a number of 24 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 255677754133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (255677754133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127838877065 + 127838877066.
It is an arithmetic number, because the mean of its divisors is an integer number (127838877066).
Almost surely, 2255677754131 is an apocalyptic number.
255677754131 is a deficient number, since it is larger than the sum of its proper divisors (1).
255677754131 is an equidigital number, since it uses as much as digits as its factorization.
255677754131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6174000, while the sum is 53.
The spelling of 255677754131 in words is "two hundred fifty-five billion, six hundred seventy-seven million, seven hundred fifty-four thousand, one hundred thirty-one".
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