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25573938251413 is a prime number
BaseRepresentation
bin1011101000010011001011…
…00000010100011010010101
310100112211210201122200111111
411310021211200110122111
511323000411143021123
6130220301031135021
75246441013310546
oct564114540243225
9110484721580444
1025573938251413
11816a9344826a2
122a50498214471
1311367c5821c96
14645adc8bc4cd
152e538442590d
hex174265814695

25573938251413 has 2 divisors, whose sum is σ = 25573938251414. Its totient is φ = 25573938251412.

The previous prime is 25573938251363. The next prime is 25573938251423. The reversal of 25573938251413 is 31415283937552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25568222589009 + 5715662404 = 5056503^2 + 75602^2 .

It is a cyclic number.

It is not a de Polignac number, because 25573938251413 - 29 = 25573938250901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25573938251423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12786969125706 + 12786969125707.

It is an arithmetic number, because the mean of its divisors is an integer number (12786969125707).

Almost surely, 225573938251413 is an apocalyptic number.

It is an amenable number.

25573938251413 is a deficient number, since it is larger than the sum of its proper divisors (1).

25573938251413 is an equidigital number, since it uses as much as digits as its factorization.

25573938251413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 27216000, while the sum is 58.

The spelling of 25573938251413 in words is "twenty-five trillion, five hundred seventy-three billion, nine hundred thirty-eight million, two hundred fifty-one thousand, four hundred thirteen".