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255912901117 = 2484110302037
BaseRepresentation
bin1110111001010110011…
…0001111100111111101
3220110120000021100120221
43232111212033213331
513143102200313432
6313321553341341
724326521524346
oct3562546174775
9813500240527
10255912901117
1199594185395
1241720867851
131b1950b0353
14c559c2b0cd
1569cbe99b97
hex3b9598f9fd

255912901117 has 4 divisors (see below), whose sum is σ = 255923227996. Its totient is φ = 255902574240.

The previous prime is 255912901109. The next prime is 255912901169. The reversal of 255912901117 is 711109219552.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 155858354521 + 100054546596 = 394789^2 + 316314^2 .

It is a cyclic number.

It is not a de Polignac number, because 255912901117 - 23 = 255912901109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255912901817) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5126178 + ... + 5175859.

It is an arithmetic number, because the mean of its divisors is an integer number (63980806999).

Almost surely, 2255912901117 is an apocalyptic number.

It is an amenable number.

255912901117 is a deficient number, since it is larger than the sum of its proper divisors (10326879).

255912901117 is a wasteful number, since it uses less digits than its factorization.

255912901117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10326878.

The product of its (nonzero) digits is 56700, while the sum is 43.

The spelling of 255912901117 in words is "two hundred fifty-five billion, nine hundred twelve million, nine hundred one thousand, one hundred seventeen".

Divisors: 1 24841 10302037 255912901117