Base | Representation |
---|---|
bin | 100101010000010011101… |
… | …001011010011000110111 |
3 | 100001202010212111201211102 |
4 | 211100103221122120313 |
5 | 313421121303202021 |
6 | 5240035121400315 |
7 | 352651261031321 |
oct | 45202351323067 |
9 | 10052125451742 |
10 | 2560130131511 |
11 | 8a7821798047 |
12 | 35420649909b |
13 | 15755b0a2904 |
14 | 8bca795c611 |
15 | 468dc9bb00b |
hex | 25413a5a637 |
2560130131511 has 2 divisors, whose sum is σ = 2560130131512. Its totient is φ = 2560130131510.
The previous prime is 2560130131487. The next prime is 2560130131529. The reversal of 2560130131511 is 1151310310652.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2560130131511 - 234 = 2542950262327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2560130131211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280065065755 + 1280065065756.
It is an arithmetic number, because the mean of its divisors is an integer number (1280065065756).
Almost surely, 22560130131511 is an apocalyptic number.
2560130131511 is a deficient number, since it is larger than the sum of its proper divisors (1).
2560130131511 is an equidigital number, since it uses as much as digits as its factorization.
2560130131511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 29.
The spelling of 2560130131511 in words is "two trillion, five hundred sixty billion, one hundred thirty million, one hundred thirty-one thousand, five hundred eleven".
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