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2560134342143 = 7365733477449
BaseRepresentation
bin100101010000010011111…
…001011110010111111111
3100001202011011102122201202
4211100103321132113333
5313421123342422033
65240035351530115
7352651341566240
oct45202371362777
910052134378652
102560134342143
118a7824103604
1235420798993b
1315755bc18301
148bca8336cc7
15468dd04d8e8
hex25413e5e5ff

2560134342143 has 4 divisors (see below), whose sum is σ = 2925867819600. Its totient is φ = 2194400864688.

The previous prime is 2560134342131. The next prime is 2560134342163. The reversal of 2560134342143 is 3412434310652.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2560134342143 - 216 = 2560134276607 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2560134342097 and 2560134342106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2560134342163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182866738718 + ... + 182866738731.

It is an arithmetic number, because the mean of its divisors is an integer number (731466954900).

Almost surely, 22560134342143 is an apocalyptic number.

2560134342143 is a deficient number, since it is larger than the sum of its proper divisors (365733477457).

2560134342143 is an equidigital number, since it uses as much as digits as its factorization.

2560134342143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 365733477456.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 2560134342143 its reverse (3412434310652), we get a palindrome (5972568652795).

The spelling of 2560134342143 in words is "two trillion, five hundred sixty billion, one hundred thirty-four million, three hundred forty-two thousand, one hundred forty-three".

Divisors: 1 7 365733477449 2560134342143