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256020043 is a prime number
BaseRepresentation
bin11110100001010…
…00111001001011
3122211202011110211
433100220321023
51011020120133
641223221551
76226064056
oct1720507113
9584664424
10256020043
11121575714
12718a78b7
134106c866
1426005a9d
1517722bcd
hexf428e4b

256020043 has 2 divisors, whose sum is σ = 256020044. Its totient is φ = 256020042.

The previous prime is 256020013. The next prime is 256020049. The reversal of 256020043 is 340020652.

It is a happy number.

256020043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 256020043 - 29 = 256019531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 256019996 and 256020023.

It is not a weakly prime, because it can be changed into another prime (256020049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128010021 + 128010022.

It is an arithmetic number, because the mean of its divisors is an integer number (128010022).

Almost surely, 2256020043 is an apocalyptic number.

256020043 is a deficient number, since it is larger than the sum of its proper divisors (1).

256020043 is an equidigital number, since it uses as much as digits as its factorization.

256020043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 256020043 is about 16000.6263314909. The cubic root of 256020043 is about 634.9769913336.

Adding to 256020043 its reverse (340020652), we get a palindrome (596040695).

The spelling of 256020043 in words is "two hundred fifty-six million, twenty thousand, forty-three".