Base | Representation |
---|---|
bin | 10111110110010110… |
… | …110001001111110001 |
3 | 2110002122222012200212 |
4 | 113312112301033301 |
5 | 404421122003442 |
6 | 15433020153505 |
7 | 1564406261402 |
oct | 276626611761 |
9 | 73078865625 |
10 | 25608000497 |
11 | a951059882 |
12 | 4b68098895 |
13 | 25514a3821 |
14 | 134d0139a9 |
15 | 9ed270a82 |
hex | 5f65b13f1 |
25608000497 has 2 divisors, whose sum is σ = 25608000498. Its totient is φ = 25608000496.
The previous prime is 25608000493. The next prime is 25608000499. The reversal of 25608000497 is 79400080652.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20380132081 + 5227868416 = 142759^2 + 72304^2 .
It is a cyclic number.
It is not a de Polignac number, because 25608000497 - 22 = 25608000493 is a prime.
Together with 25608000499, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (25608000493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12804000248 + 12804000249.
It is an arithmetic number, because the mean of its divisors is an integer number (12804000249).
Almost surely, 225608000497 is an apocalyptic number.
It is an amenable number.
25608000497 is a deficient number, since it is larger than the sum of its proper divisors (1).
25608000497 is an equidigital number, since it uses as much as digits as its factorization.
25608000497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 25608000497 in words is "twenty-five billion, six hundred eight million, four hundred ninety-seven", and thus it is an aban number.
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