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2561010243 = 31177606371
BaseRepresentation
bin1001100010100101…
…1110101001000011
320121110222210121020
42120221132221003
520221104311433
61102043200523
7120315141111
oct23051365103
96543883536
102561010243
1110a46949a0
125b5816143
1331a77119c
141a41b2ab1
15eec7ccb3
hex98a5ea43

2561010243 has 8 divisors (see below), whose sum is σ = 3725105856. Its totient is φ = 1552127400.

The previous prime is 2561010239. The next prime is 2561010259. The reversal of 2561010243 is 3420101652.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2561010243 - 22 = 2561010239 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2561014243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38803153 + ... + 38803218.

It is an arithmetic number, because the mean of its divisors is an integer number (465638232).

Almost surely, 22561010243 is an apocalyptic number.

2561010243 is a deficient number, since it is larger than the sum of its proper divisors (1164095613).

2561010243 is a wasteful number, since it uses less digits than its factorization.

2561010243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77606385.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 2561010243 is about 50606.4249181860. The cubic root of 2561010243 is about 1368.1606806791.

Adding to 2561010243 its reverse (3420101652), we get a palindrome (5981111895).

It can be divided in two parts, 25610 and 10243, that added together give a palindrome (35853).

The spelling of 2561010243 in words is "two billion, five hundred sixty-one million, ten thousand, two hundred forty-three".

Divisors: 1 3 11 33 77606371 232819113 853670081 2561010243