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2561038841 is a prime number
BaseRepresentation
bin1001100010100110…
…0101100111111001
320121111001020211102
42120221211213321
520221111220331
61102043541145
7120315320354
oct23051454771
96544036742
102561038841
1110a4704429
125b582a7b5
1331a7811ca
141a41bd29b
15eec864cb
hex98a659f9

2561038841 has 2 divisors, whose sum is σ = 2561038842. Its totient is φ = 2561038840.

The previous prime is 2561038771. The next prime is 2561038847. The reversal of 2561038841 is 1488301652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2540563216 + 20475625 = 50404^2 + 4525^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2561038841 is a prime.

It is a super-2 number, since 2×25610388412 = 13117839890221246562, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2561038795 and 2561038804.

It is not a weakly prime, because it can be changed into another prime (2561038847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280519420 + 1280519421.

It is an arithmetic number, because the mean of its divisors is an integer number (1280519421).

Almost surely, 22561038841 is an apocalyptic number.

It is an amenable number.

2561038841 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561038841 is an equidigital number, since it uses as much as digits as its factorization.

2561038841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 38.

The square root of 2561038841 is about 50606.7074704530. The cubic root of 2561038841 is about 1368.1657732675.

The spelling of 2561038841 in words is "two billion, five hundred sixty-one million, thirty-eight thousand, eight hundred forty-one".