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2561044506121 is a prime number
BaseRepresentation
bin100101010001001010001…
…001011110011000001001
3100001211111121001202222201
4211101022021132120021
5313430004343143441
65240305543520201
7353013033056443
oct45211211363011
910054447052881
102561044506121
118a8150948242
12354420759061
1315767566008a
148bd5317b493
1546942dd6c31
hex2544a25e609

2561044506121 has 2 divisors, whose sum is σ = 2561044506122. Its totient is φ = 2561044506120.

The previous prime is 2561044506079. The next prime is 2561044506131. The reversal of 2561044506121 is 1216054401652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2443628630521 + 117415875600 = 1563211^2 + 342660^2 .

It is a cyclic number.

It is not a de Polignac number, because 2561044506121 - 213 = 2561044497929 is a prime.

It is not a weakly prime, because it can be changed into another prime (2561044506131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280522253060 + 1280522253061.

It is an arithmetic number, because the mean of its divisors is an integer number (1280522253061).

Almost surely, 22561044506121 is an apocalyptic number.

It is an amenable number.

2561044506121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561044506121 is an equidigital number, since it uses as much as digits as its factorization.

2561044506121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 37.

Adding to 2561044506121 its reverse (1216054401652), we get a palindrome (3777098907773).

The spelling of 2561044506121 in words is "two trillion, five hundred sixty-one billion, forty-four million, five hundred six thousand, one hundred twenty-one".