Base | Representation |
---|---|
bin | 1011101001011100010101… |
… | …11000101111011010000110 |
3 | 10100200121012100102011112212 |
4 | 11310232022320233122012 |
5 | 11324121333322203402 |
6 | 130250314553543422 |
7 | 5252331320535443 |
oct | 564561270573206 |
9 | 110617170364485 |
10 | 25613220116102 |
11 | 8185562024a83 |
12 | 2a5801b714b72 |
13 | 113a415b856b8 |
14 | 6479879509ca |
15 | 2e63d2d56952 |
hex | 174b8ae2f686 |
25613220116102 has 4 divisors (see below), whose sum is σ = 38419830174156. Its totient is φ = 12806610058050.
The previous prime is 25613220116053. The next prime is 25613220116111. The reversal of 25613220116102 is 20161102231652.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6403305029024 + ... + 6403305029027.
It is an arithmetic number, because the mean of its divisors is an integer number (9604957543539).
Almost surely, 225613220116102 is an apocalyptic number.
25613220116102 is a deficient number, since it is larger than the sum of its proper divisors (12806610058054).
25613220116102 is a wasteful number, since it uses less digits than its factorization.
25613220116102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12806610058053.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 25613220116102 its reverse (20161102231652), we get a palindrome (45774322347754).
The spelling of 25613220116102 in words is "twenty-five trillion, six hundred thirteen billion, two hundred twenty million, one hundred sixteen thousand, one hundred two".
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