Base | Representation |
---|---|
bin | 1011101001011100010101… |
… | …11000101111011010100110 |
3 | 10100200121012100102011121001 |
4 | 11310232022320233122212 |
5 | 11324121333322204014 |
6 | 130250314553543514 |
7 | 5252331320535520 |
oct | 564561270573246 |
9 | 110617170364531 |
10 | 25613220116134 |
11 | 8185562025002 |
12 | 2a5801b714b9a |
13 | 113a415b85711 |
14 | 647987950a10 |
15 | 2e63d2d56974 |
hex | 174b8ae2f6a6 |
25613220116134 has 16 divisors (see below), whose sum is σ = 44736837293088. Its totient is φ = 10769979347712.
The previous prime is 25613220116111. The next prime is 25613220116213. The reversal of 25613220116134 is 43161102231652.
It is a junction number, because it is equal to n+sod(n) for n = 25613220116093 and 25613220116102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17259581547 + ... + 17259583030.
It is an arithmetic number, because the mean of its divisors is an integer number (2796052330818).
Almost surely, 225613220116134 is an apocalyptic number.
25613220116134 is a deficient number, since it is larger than the sum of its proper divisors (19123617176954).
25613220116134 is a wasteful number, since it uses less digits than its factorization.
25613220116134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34519164639.
The product of its (nonzero) digits is 51840, while the sum is 37.
Adding to 25613220116134 its reverse (43161102231652), we get a palindrome (68774322347786).
The spelling of 25613220116134 in words is "twenty-five trillion, six hundred thirteen billion, two hundred twenty million, one hundred sixteen thousand, one hundred thirty-four".
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