Search a number
-
+
256148307 = 3228460923
BaseRepresentation
bin11110100010010…
…00001101010011
3122211222200102100
433101020031103
51011033221212
641230051443
76230140032
oct1721101523
9584880370
10256148307
11121653018
1271949b83
13410b605c
142603a719
151774abdc
hexf448353

256148307 has 6 divisors (see below), whose sum is σ = 369992012. Its totient is φ = 170765532.

The previous prime is 256148297. The next prime is 256148327. The reversal of 256148307 is 703841652.

256148307 is a `hidden beast` number, since 2 + 5 + 614 + 8 + 30 + 7 = 666.

It is not a de Polignac number, because 256148307 - 214 = 256131923 is a prime.

It is a super-2 number, since 2×2561483072 = 131223910357932498, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (256148327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 14230453 + ... + 14230470.

Almost surely, 2256148307 is an apocalyptic number.

256148307 is a deficient number, since it is larger than the sum of its proper divisors (113843705).

256148307 is a wasteful number, since it uses less digits than its factorization.

256148307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28460929 (or 28460926 counting only the distinct ones).

The product of its (nonzero) digits is 40320, while the sum is 36.

The square root of 256148307 is about 16004.6339227113. The cubic root of 256148307 is about 635.0830131000.

Adding to 256148307 its reverse (703841652), we get a palindrome (959989959).

The spelling of 256148307 in words is "two hundred fifty-six million, one hundred forty-eight thousand, three hundred seven".

Divisors: 1 3 9 28460923 85382769 256148307