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2561490742553 is a prime number
BaseRepresentation
bin100101010001100100101…
…111101110110100011001
3100001212122200201221021222
4211101210233232310121
5313431413112230203
65240422124141425
7353030062032341
oct45214457566431
910055580657258
102561490742553
118a835a823286
12354526097875
13157716c3c9c2
148bd96539d21
154696c180038
hex25464beed19

2561490742553 has 2 divisors, whose sum is σ = 2561490742554. Its totient is φ = 2561490742552.

The previous prime is 2561490742469. The next prime is 2561490742607. The reversal of 2561490742553 is 3552470941652.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2533610759824 + 27879982729 = 1591732^2 + 166973^2 .

It is a cyclic number.

It is not a de Polignac number, because 2561490742553 - 210 = 2561490741529 is a prime.

It is a super-2 number, since 2×25614907425532 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2561490742495 and 2561490742504.

It is not a weakly prime, because it can be changed into another prime (2561490742253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280745371276 + 1280745371277.

It is an arithmetic number, because the mean of its divisors is an integer number (1280745371277).

Almost surely, 22561490742553 is an apocalyptic number.

It is an amenable number.

2561490742553 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561490742553 is an equidigital number, since it uses as much as digits as its factorization.

2561490742553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072000, while the sum is 53.

The spelling of 2561490742553 in words is "two trillion, five hundred sixty-one billion, four hundred ninety million, seven hundred forty-two thousand, five hundred fifty-three".