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256477007114149 is a prime number
BaseRepresentation
bin111010010100001110110100…
…111001101110111110100101
31020122002221222121100222001011
4322110032310321232332211
5232104104402310123044
62305251524355502221
7105010565221110043
oct7224166471567645
91218087877328034
10256477007114149
11747a33191a0888
1224922b668b7971
13b0158a77216c3
1447497a6685393
151e9b84ee13134
hexe943b4e6efa5

256477007114149 has 2 divisors, whose sum is σ = 256477007114150. Its totient is φ = 256477007114148.

The previous prime is 256477007114129. The next prime is 256477007114171. The reversal of 256477007114149 is 941411700774652.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 163857459665124 + 92619547449025 = 12800682^2 + 9623905^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-256477007114149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 256477007114093 and 256477007114102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (256477007114129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128238503557074 + 128238503557075.

It is an arithmetic number, because the mean of its divisors is an integer number (128238503557075).

Almost surely, 2256477007114149 is an apocalyptic number.

It is an amenable number.

256477007114149 is a deficient number, since it is larger than the sum of its proper divisors (1).

256477007114149 is an equidigital number, since it uses as much as digits as its factorization.

256477007114149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11854080, while the sum is 58.

The spelling of 256477007114149 in words is "two hundred fifty-six trillion, four hundred seventy-seven billion, seven million, one hundred fourteen thousand, one hundred forty-nine".