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256542113 = 1511169783
BaseRepresentation
bin11110100101010…
…00010110100001
3122212201200121202
433102220112201
51011133321423
641242330545
76233400122
oct1722502641
9585650552
10256542113
111218a1983
1271ab9a55
13411c3389
1426100049
15177c7728
hexf4a85a1

256542113 has 4 divisors (see below), whose sum is σ = 256713408. Its totient is φ = 256370820.

The previous prime is 256542109. The next prime is 256542119. The reversal of 256542113 is 311245652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 256542113 - 22 = 256542109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (256542119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83381 + ... + 86402.

It is an arithmetic number, because the mean of its divisors is an integer number (64178352).

Almost surely, 2256542113 is an apocalyptic number.

It is an amenable number.

256542113 is a deficient number, since it is larger than the sum of its proper divisors (171295).

256542113 is a wasteful number, since it uses less digits than its factorization.

256542113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171294.

The product of its digits is 7200, while the sum is 29.

The square root of 256542113 is about 16016.9320720293. The cubic root of 256542113 is about 635.4083082965.

Adding to 256542113 its reverse (311245652), we get a palindrome (567787765).

The spelling of 256542113 in words is "two hundred fifty-six million, five hundred forty-two thousand, one hundred thirteen".

Divisors: 1 1511 169783 256542113