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25671002117 is a prime number
BaseRepresentation
bin10111111010000111…
…000110100000000101
32110021001112000200012
4113322013012200011
5410033234031432
615443150400005
71566102626525
oct277207064005
973231460605
1025671002117
11a98367a932
124b85200005
132561561aa7
141357533685
15a03a67cb2
hex5fa1c6805

25671002117 has 2 divisors, whose sum is σ = 25671002118. Its totient is φ = 25671002116.

The previous prime is 25671002089. The next prime is 25671002141. The reversal of 25671002117 is 71120017652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25553301316 + 117700801 = 159854^2 + 10849^2 .

It is a cyclic number.

It is not a de Polignac number, because 25671002117 - 210 = 25671001093 is a prime.

It is a super-3 number, since 3×256710021173 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25671002417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12835501058 + 12835501059.

It is an arithmetic number, because the mean of its divisors is an integer number (12835501059).

Almost surely, 225671002117 is an apocalyptic number.

It is an amenable number.

25671002117 is a deficient number, since it is larger than the sum of its proper divisors (1).

25671002117 is an equidigital number, since it uses as much as digits as its factorization.

25671002117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5880, while the sum is 32.

Adding to 25671002117 its reverse (71120017652), we get a palindrome (96791019769).

The spelling of 25671002117 in words is "twenty-five billion, six hundred seventy-one million, two thousand, one hundred seventeen".