Base | Representation |
---|---|
bin | 10111111011101111… |
… | …001100111100011001 |
3 | 2110022221212110122101 |
4 | 113323233030330121 |
5 | 410112230311411 |
6 | 15450003323401 |
7 | 1566553605412 |
oct | 277357147431 |
9 | 73287773571 |
10 | 25698291481 |
11 | a998019825 |
12 | 4b92380561 |
13 | 25670c8045 |
14 | 135add8809 |
15 | a061588c1 |
hex | 5fbbccf19 |
25698291481 has 2 divisors, whose sum is σ = 25698291482. Its totient is φ = 25698291480.
The previous prime is 25698291469. The next prime is 25698291547. The reversal of 25698291481 is 18419289652.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20251851481 + 5446440000 = 142309^2 + 73800^2 .
It is a cyclic number.
It is not a de Polignac number, because 25698291481 - 227 = 25564073753 is a prime.
It is a super-2 number, since 2×256982914812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (25698291431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12849145740 + 12849145741.
It is an arithmetic number, because the mean of its divisors is an integer number (12849145741).
Almost surely, 225698291481 is an apocalyptic number.
It is an amenable number.
25698291481 is a deficient number, since it is larger than the sum of its proper divisors (1).
25698291481 is an equidigital number, since it uses as much as digits as its factorization.
25698291481 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2488320, while the sum is 55.
The spelling of 25698291481 in words is "twenty-five billion, six hundred ninety-eight million, two hundred ninety-one thousand, four hundred eighty-one".
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