Base | Representation |
---|---|
bin | 110001000010… |
… | …1101011111111 |
3 | 1210101101011102 |
4 | 1202011223333 |
5 | 23040312112 |
6 | 2315043315 |
7 | 431363126 |
oct | 142055377 |
9 | 53341142 |
10 | 25713407 |
11 | 13572955 |
12 | 874053b |
13 | 5433b45 |
14 | 35b4abd |
15 | 23cdbc2 |
hex | 1885aff |
25713407 has 2 divisors, whose sum is σ = 25713408. Its totient is φ = 25713406.
The previous prime is 25713397. The next prime is 25713419. The reversal of 25713407 is 70431752.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25713407 - 210 = 25712383 is a prime.
It is a super-2 number, since 2×257134072 = 1322358599095298, which contains 22 as substring.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 25713407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25713007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12856703 + 12856704.
It is an arithmetic number, because the mean of its divisors is an integer number (12856704).
Almost surely, 225713407 is an apocalyptic number.
25713407 is a deficient number, since it is larger than the sum of its proper divisors (1).
25713407 is an equidigital number, since it uses as much as digits as its factorization.
25713407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5880, while the sum is 29.
The square root of 25713407 is about 5070.8388852339. The cubic root of 25713407 is about 295.1570819075.
The spelling of 25713407 in words is "twenty-five million, seven hundred thirteen thousand, four hundred seven".
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