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2573481068113 is a prime number
BaseRepresentation
bin100101011100101111011…
…011001100011001010001
3100010000121022122120210211
4211130233123030121101
5314130442123134423
65250124010324121
7353633155103614
oct45345733143121
910100538576724
102573481068113
11902452a7734a
12356911729641
131588a8097bb7
148c7b2b5a17b
1546e1eb3e10d
hex2572f6cc651

2573481068113 has 2 divisors, whose sum is σ = 2573481068114. Its totient is φ = 2573481068112.

The previous prime is 2573481068101. The next prime is 2573481068149. The reversal of 2573481068113 is 3118601843752.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2546121261649 + 27359806464 = 1595657^2 + 165408^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2573481068113 is a prime.

It is not a weakly prime, because it can be changed into another prime (2573481068153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1286740534056 + 1286740534057.

It is an arithmetic number, because the mean of its divisors is an integer number (1286740534057).

Almost surely, 22573481068113 is an apocalyptic number.

It is an amenable number.

2573481068113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2573481068113 is an equidigital number, since it uses as much as digits as its factorization.

2573481068113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 967680, while the sum is 49.

The spelling of 2573481068113 in words is "two trillion, five hundred seventy-three billion, four hundred eighty-one million, sixty-eight thousand, one hundred thirteen".