Base | Representation |
---|---|
bin | 100101011100101111011… |
… | …011001100011001010001 |
3 | 100010000121022122120210211 |
4 | 211130233123030121101 |
5 | 314130442123134423 |
6 | 5250124010324121 |
7 | 353633155103614 |
oct | 45345733143121 |
9 | 10100538576724 |
10 | 2573481068113 |
11 | 902452a7734a |
12 | 356911729641 |
13 | 1588a8097bb7 |
14 | 8c7b2b5a17b |
15 | 46e1eb3e10d |
hex | 2572f6cc651 |
2573481068113 has 2 divisors, whose sum is σ = 2573481068114. Its totient is φ = 2573481068112.
The previous prime is 2573481068101. The next prime is 2573481068149. The reversal of 2573481068113 is 3118601843752.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2546121261649 + 27359806464 = 1595657^2 + 165408^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2573481068113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2573481068153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1286740534056 + 1286740534057.
It is an arithmetic number, because the mean of its divisors is an integer number (1286740534057).
Almost surely, 22573481068113 is an apocalyptic number.
It is an amenable number.
2573481068113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2573481068113 is an equidigital number, since it uses as much as digits as its factorization.
2573481068113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 967680, while the sum is 49.
The spelling of 2573481068113 in words is "two trillion, five hundred seventy-three billion, four hundred eighty-one million, sixty-eight thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •