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2573481068153 is a prime number
BaseRepresentation
bin100101011100101111011…
…011001100011001111001
3100010000121022122120212022
4211130233123030121321
5314130442123140103
65250124010324225
7353633155104002
oct45345733143171
910100538576768
102573481068153
11902452a77386
12356911729675
131588a8097c18
148c7b2b5a1a9
1546e1eb3e138
hex2572f6cc679

2573481068153 has 2 divisors, whose sum is σ = 2573481068154. Its totient is φ = 2573481068152.

The previous prime is 2573481068149. The next prime is 2573481068177. The reversal of 2573481068153 is 3518601843752.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2538200207929 + 35280860224 = 1593173^2 + 187832^2 .

It is a cyclic number.

It is not a de Polignac number, because 2573481068153 - 22 = 2573481068149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2573481068095 and 2573481068104.

It is not a weakly prime, because it can be changed into another prime (2573481068113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1286740534076 + 1286740534077.

It is an arithmetic number, because the mean of its divisors is an integer number (1286740534077).

Almost surely, 22573481068153 is an apocalyptic number.

It is an amenable number.

2573481068153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2573481068153 is an equidigital number, since it uses as much as digits as its factorization.

2573481068153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 2573481068153 in words is "two trillion, five hundred seventy-three billion, four hundred eighty-one million, sixty-eight thousand, one hundred fifty-three".