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257413141706123 = 1319801010900471
BaseRepresentation
bin111010100001110110101010…
…110111110011010110001011
31020202102110022102202111210202
4322201312222313303112023
5232214424103234043443
62311245544221002415
7105135325421622164
oct7241665267632613
91222373272674722
10257413141706123
1175024333823427
1224a544843b340b
13b082c554a4280
14477cc10b1c76b
151eb5d8e8da7b8
hexea1daadf358b

257413141706123 has 4 divisors (see below), whose sum is σ = 277214152606608. Its totient is φ = 237612130805640.

The previous prime is 257413141706107. The next prime is 257413141706173. The reversal of 257413141706123 is 321607141314752.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 257413141706123 - 24 = 257413141706107 is a prime.

It is a super-3 number, since 3×2574131417061233 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (257413141706173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9900505450223 + ... + 9900505450248.

It is an arithmetic number, because the mean of its divisors is an integer number (69303538151652).

Almost surely, 2257413141706123 is an apocalyptic number.

257413141706123 is a deficient number, since it is larger than the sum of its proper divisors (19801010900485).

257413141706123 is a wasteful number, since it uses less digits than its factorization.

257413141706123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19801010900484.

The product of its (nonzero) digits is 846720, while the sum is 47.

The spelling of 257413141706123 in words is "two hundred fifty-seven trillion, four hundred thirteen billion, one hundred forty-one million, seven hundred six thousand, one hundred twenty-three".

Divisors: 1 13 19801010900471 257413141706123