Base | Representation |
---|---|
bin | 11110101110001… |
… | …10101110101001 |
3 | 122221221021200012 |
4 | 33113012232221 |
5 | 1011433340423 |
6 | 41323421305 |
7 | 6246354005 |
oct | 1727065651 |
9 | 587837605 |
10 | 257715113 |
11 | 1225231a7 |
12 | 72384835 |
13 | 41514266 |
14 | 26327705 |
15 | 1795a078 |
hex | f5c6ba9 |
257715113 has 4 divisors (see below), whose sum is σ = 257758080. Its totient is φ = 257672148.
The previous prime is 257715103. The next prime is 257715137. The reversal of 257715113 is 311517752.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 257715113 - 28 = 257714857 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 257715113.
It is not an unprimeable number, because it can be changed into a prime (257715103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10673 + ... + 25086.
It is an arithmetic number, because the mean of its divisors is an integer number (64439520).
Almost surely, 2257715113 is an apocalyptic number.
It is an amenable number.
257715113 is a deficient number, since it is larger than the sum of its proper divisors (42967).
257715113 is an equidigital number, since it uses as much as digits as its factorization.
257715113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42966.
The product of its digits is 7350, while the sum is 32.
The square root of 257715113 is about 16053.5078098215. The cubic root of 257715113 is about 636.3752721453.
The spelling of 257715113 in words is "two hundred fifty-seven million, seven hundred fifteen thousand, one hundred thirteen".
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