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258038121433 is a prime number
BaseRepresentation
bin1111000001010001000…
…1010100001111011001
3220200001010020201210111
43300110101110033121
513211430224341213
6314312512244321
724433265562061
oct3602421241731
9820033221714
10258038121433
119a484879914
12420145406a1
131b44348b771
14c6bc1a03a1
156aa3844a3d
hex3c144543d9

258038121433 has 2 divisors, whose sum is σ = 258038121434. Its totient is φ = 258038121432.

The previous prime is 258038121427. The next prime is 258038121461. The reversal of 258038121433 is 334121830852.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 183756254224 + 74281867209 = 428668^2 + 272547^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-258038121433 is a prime.

It is a super-2 number, since 2×2580381214332 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (258038121463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129019060716 + 129019060717.

It is an arithmetic number, because the mean of its divisors is an integer number (129019060717).

Almost surely, 2258038121433 is an apocalyptic number.

It is an amenable number.

258038121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

258038121433 is an equidigital number, since it uses as much as digits as its factorization.

258038121433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 40.

The spelling of 258038121433 in words is "two hundred fifty-eight billion, thirty-eight million, one hundred twenty-one thousand, four hundred thirty-three".