Base | Representation |
---|---|
bin | 100101100100001000101… |
… | …100010101110000101101 |
3 | 100010210002200101101000112 |
4 | 211210020230111300231 |
5 | 314243222310423333 |
6 | 5253515530505405 |
7 | 354334011020621 |
oct | 45441054256055 |
9 | 10123080341015 |
10 | 2581421186093 |
11 | 905857a64522 |
12 | 358368895265 |
13 | 1595720a2969 |
14 | 8cd274b7181 |
15 | 47236c5b948 |
hex | 25908b15c2d |
2581421186093 has 2 divisors, whose sum is σ = 2581421186094. Its totient is φ = 2581421186092.
The previous prime is 2581421186023. The next prime is 2581421186101. The reversal of 2581421186093 is 3906811241852.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2508843748489 + 72577437604 = 1583933^2 + 269402^2 .
It is a cyclic number.
It is not a de Polignac number, because 2581421186093 - 214 = 2581421169709 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2581421186023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1290710593046 + 1290710593047.
It is an arithmetic number, because the mean of its divisors is an integer number (1290710593047).
Almost surely, 22581421186093 is an apocalyptic number.
It is an amenable number.
2581421186093 is a deficient number, since it is larger than the sum of its proper divisors (1).
2581421186093 is an equidigital number, since it uses as much as digits as its factorization.
2581421186093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 829440, while the sum is 50.
The spelling of 2581421186093 in words is "two trillion, five hundred eighty-one billion, four hundred twenty-one million, one hundred eighty-six thousand, ninety-three".
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