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25916325437 is a prime number
BaseRepresentation
bin11000001000101110…
…111011111000111101
32110220011010202000002
4120020232323320331
5411034034403222
615523352444045
71605142063052
oct301056737075
973804122002
1025916325437
11aa9a0a9982
1250333a9625
1325a0327912
14137bd53029
15a1a376392
hex608bbbe3d

25916325437 has 2 divisors, whose sum is σ = 25916325438. Its totient is φ = 25916325436.

The previous prime is 25916325433. The next prime is 25916325493. The reversal of 25916325437 is 73452361952.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19169510116 + 6746815321 = 138454^2 + 82139^2 .

It is a cyclic number.

It is not a de Polignac number, because 25916325437 - 22 = 25916325433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25916325391 and 25916325400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25916325433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12958162718 + 12958162719.

It is an arithmetic number, because the mean of its divisors is an integer number (12958162719).

Almost surely, 225916325437 is an apocalyptic number.

It is an amenable number.

25916325437 is a deficient number, since it is larger than the sum of its proper divisors (1).

25916325437 is an equidigital number, since it uses as much as digits as its factorization.

25916325437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1360800, while the sum is 47.

The spelling of 25916325437 in words is "twenty-five billion, nine hundred sixteen million, three hundred twenty-five thousand, four hundred thirty-seven".