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259340057 = 833124579
BaseRepresentation
bin11110111010100…
…11011100011001
3200001222211200022
433131103130121
51012342340212
641422320225
76266232314
oct1735233431
9601884608
10259340057
11123433029
1272a29075
1341962a72
142662b97b
1517b7b772
hexf753719

259340057 has 4 divisors (see below), whose sum is σ = 262464720. Its totient is φ = 256215396.

The previous prime is 259340051. The next prime is 259340089. The reversal of 259340057 is 750043952.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 259340057 - 210 = 259339033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 259339999 and 259340026.

It is not an unprimeable number, because it can be changed into a prime (259340051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1562207 + ... + 1562372.

It is an arithmetic number, because the mean of its divisors is an integer number (65616180).

Almost surely, 2259340057 is an apocalyptic number.

It is an amenable number.

259340057 is a deficient number, since it is larger than the sum of its proper divisors (3124663).

259340057 is an equidigital number, since it uses as much as digits as its factorization.

259340057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3124662.

The product of its (nonzero) digits is 37800, while the sum is 35.

The square root of 259340057 is about 16104.0385307537. The cubic root of 259340057 is about 637.7099609327.

The spelling of 259340057 in words is "two hundred fifty-nine million, three hundred forty thousand, fifty-seven".

Divisors: 1 83 3124579 259340057