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25952940133 is a prime number
BaseRepresentation
bin11000001010111010…
…100111000001100101
32110222201000221220221
4120022322213001211
5411122423041013
615531141324341
71606065231331
oct301272470145
973881027827
1025952940133
111000883805a
1250437066b1
1325a7aa7613
141382b647c1
15a1d6aa08d
hex60aea7065

25952940133 has 2 divisors, whose sum is σ = 25952940134. Its totient is φ = 25952940132.

The previous prime is 25952940113. The next prime is 25952940173. The reversal of 25952940133 is 33104925952.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25615042209 + 337897924 = 160047^2 + 18382^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25952940133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25952940133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25952940113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12976470066 + 12976470067.

It is an arithmetic number, because the mean of its divisors is an integer number (12976470067).

Almost surely, 225952940133 is an apocalyptic number.

It is an amenable number.

25952940133 is a deficient number, since it is larger than the sum of its proper divisors (1).

25952940133 is an equidigital number, since it uses as much as digits as its factorization.

25952940133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 43.

The spelling of 25952940133 in words is "twenty-five billion, nine hundred fifty-two million, nine hundred forty thousand, one hundred thirty-three".