Base | Representation |
---|---|
bin | 1011110101111010000101… |
… | …00100101000000111100101 |
3 | 10102012112200011101001220010 |
4 | 11322331002210220013211 |
5 | 11403130444411112123 |
6 | 131215145051400433 |
7 | 5325302510311341 |
oct | 572750244500745 |
9 | 112175604331803 |
10 | 26041503613413 |
11 | 8330159986542 |
12 | 2b07026a53119 |
13 | 116b91b081c62 |
14 | 6605b61bc621 |
15 | 3025ec815993 |
hex | 17af429281e5 |
26041503613413 has 4 divisors (see below), whose sum is σ = 34722004817888. Its totient is φ = 17361002408940.
The previous prime is 26041503613399. The next prime is 26041503613417. The reversal of 26041503613413 is 31431630514062.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 26041503613413 - 28 = 26041503613157 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (26041503613417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4340250602233 + ... + 4340250602238.
It is an arithmetic number, because the mean of its divisors is an integer number (8680501204472).
Almost surely, 226041503613413 is an apocalyptic number.
It is an amenable number.
26041503613413 is a deficient number, since it is larger than the sum of its proper divisors (8680501204475).
26041503613413 is an equidigital number, since it uses as much as digits as its factorization.
26041503613413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8680501204474.
The product of its (nonzero) digits is 155520, while the sum is 39.
The spelling of 26041503613413 in words is "twenty-six trillion, forty-one billion, five hundred three million, six hundred thirteen thousand, four hundred thirteen".
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