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26093483441 is a prime number
BaseRepresentation
bin11000010011010010…
…101111010110110001
32111100111111022002122
4120103102233112301
5411414412432231
615553121524025
71612422643514
oct302322572661
974314438078
1026093483441
1110080100353
1250827a3615
1325cac4503c
1413976aad7b
15a2abbc77b
hex6134af5b1

26093483441 has 2 divisors, whose sum is σ = 26093483442. Its totient is φ = 26093483440.

The previous prime is 26093483369. The next prime is 26093483443. The reversal of 26093483441 is 14438439062.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25577285041 + 516198400 = 159929^2 + 22720^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-26093483441 is a prime.

Together with 26093483443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 26093483392 and 26093483401.

It is not a weakly prime, because it can be changed into another prime (26093483443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13046741720 + 13046741721.

It is an arithmetic number, because the mean of its divisors is an integer number (13046741721).

Almost surely, 226093483441 is an apocalyptic number.

It is an amenable number.

26093483441 is a deficient number, since it is larger than the sum of its proper divisors (1).

26093483441 is an equidigital number, since it uses as much as digits as its factorization.

26093483441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 44.

The spelling of 26093483441 in words is "twenty-six billion, ninety-three million, four hundred eighty-three thousand, four hundred forty-one".