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261334044759071 is a prime number
BaseRepresentation
bin111011011010111010010010…
…111001111101010000011111
31021021022021211220120222111102
4323122322102321331100133
5233223144110424242241
62323451111444543315
7106021522151646164
oct7332722271752037
91237267756528442
10261334044759071
11762a6167335a69
12253883569b1b3b
13b2a890529004b
1448768c71d606b
152032d7180839b
hexedae92e7d41f

261334044759071 has 2 divisors, whose sum is σ = 261334044759072. Its totient is φ = 261334044759070.

The previous prime is 261334044758933. The next prime is 261334044759079. The reversal of 261334044759071 is 170957440433162.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-261334044759071 is a prime.

It is a super-2 number, since 2×2613340447590712 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 261334044758998 and 261334044759016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (261334044759079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130667022379535 + 130667022379536.

It is an arithmetic number, because the mean of its divisors is an integer number (130667022379536).

Almost surely, 2261334044759071 is an apocalyptic number.

261334044759071 is a deficient number, since it is larger than the sum of its proper divisors (1).

261334044759071 is an equidigital number, since it uses as much as digits as its factorization.

261334044759071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 56.

The spelling of 261334044759071 in words is "two hundred sixty-one trillion, three hundred thirty-four billion, forty-four million, seven hundred fifty-nine thousand, seventy-one".