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26134455443147 is a prime number
BaseRepresentation
bin1011111000100111001101…
…11011101101111011001011
310102112102121010122021011122
411330103212323231323023
511411141331043140042
6131330000355545455
75335103111653442
oct574234673557313
9112472533567148
1026134455443147
118366618856a37
122b210482bb28b
1311776125c113c
14664cb3143d59
15304c3cdbd7d2
hex17c4e6eedecb

26134455443147 has 2 divisors, whose sum is σ = 26134455443148. Its totient is φ = 26134455443146.

The previous prime is 26134455443113. The next prime is 26134455443249. The reversal of 26134455443147 is 74134455443162.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 26134455443147 - 214 = 26134455426763 is a prime.

It is a super-2 number, since 2×261344554431472 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (26134455448147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13067227721573 + 13067227721574.

It is an arithmetic number, because the mean of its divisors is an integer number (13067227721574).

Almost surely, 226134455443147 is an apocalyptic number.

26134455443147 is a deficient number, since it is larger than the sum of its proper divisors (1).

26134455443147 is an equidigital number, since it uses as much as digits as its factorization.

26134455443147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19353600, while the sum is 53.

The spelling of 26134455443147 in words is "twenty-six trillion, one hundred thirty-four billion, four hundred fifty-five million, four hundred forty-three thousand, one hundred forty-seven".