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26137458041 is a prime number
BaseRepresentation
bin11000010101111010…
…011111010101111001
32111110120020102220112
4120111322133111321
5412012142124131
620001332234105
71613465504402
oct302572372571
974416212815
1026137458041
11100a2a060a2
12509546b935
1326070a0a06
14139d4769a9
15a2e9a702b
hex615e9f579

26137458041 has 2 divisors, whose sum is σ = 26137458042. Its totient is φ = 26137458040.

The previous prime is 26137458001. The next prime is 26137458043. The reversal of 26137458041 is 14085473162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17101054441 + 9036403600 = 130771^2 + 95060^2 .

It is a cyclic number.

It is not a de Polignac number, because 26137458041 - 226 = 26070349177 is a prime.

Together with 26137458043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 26137458041.

It is not a weakly prime, because it can be changed into another prime (26137458043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13068729020 + 13068729021.

It is an arithmetic number, because the mean of its divisors is an integer number (13068729021).

Almost surely, 226137458041 is an apocalyptic number.

It is an amenable number.

26137458041 is a deficient number, since it is larger than the sum of its proper divisors (1).

26137458041 is an equidigital number, since it uses as much as digits as its factorization.

26137458041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 41.

The spelling of 26137458041 in words is "twenty-six billion, one hundred thirty-seven million, four hundred fifty-eight thousand, forty-one".