Base | Representation |
---|---|
bin | 1011111010111010101100… |
… | …10110110000010100001011 |
3 | 10102210222222020110112101002 |
4 | 11331131112112300110023 |
5 | 11413441010324310011 |
6 | 131430213255445215 |
7 | 5343605202260441 |
oct | 575352626602413 |
9 | 112728866415332 |
10 | 26213634213131 |
11 | 839715a141822 |
12 | 2b3446508680b |
13 | 1181c2054bb21 |
14 | 668a64bc8b91 |
15 | 306d2421ec3b |
hex | 17d7565b050b |
26213634213131 has 2 divisors, whose sum is σ = 26213634213132. Its totient is φ = 26213634213130.
The previous prime is 26213634213073. The next prime is 26213634213133. The reversal of 26213634213131 is 13131243631262.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26213634213131 - 210 = 26213634212107 is a prime.
It is a super-2 number, since 2×262136342131312 (a number of 28 digits) contains 22 as substring.
Together with 26213634213133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (26213634213133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13106817106565 + 13106817106566.
It is an arithmetic number, because the mean of its divisors is an integer number (13106817106566).
Almost surely, 226213634213131 is an apocalyptic number.
26213634213131 is a deficient number, since it is larger than the sum of its proper divisors (1).
26213634213131 is an equidigital number, since it uses as much as digits as its factorization.
26213634213131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 93312, while the sum is 38.
Adding to 26213634213131 its reverse (13131243631262), we get a palindrome (39344877844393).
The spelling of 26213634213131 in words is "twenty-six trillion, two hundred thirteen billion, six hundred thirty-four million, two hundred thirteen thousand, one hundred thirty-one".
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