Base | Representation |
---|---|
bin | 1011111100111111110000… |
… | …10001011011000100010011 |
3 | 10110001211100201212201102112 |
4 | 11332133320101123010103 |
5 | 11421123310432413412 |
6 | 131523110004535535 |
7 | 5352014354201114 |
oct | 576377021330423 |
9 | 113054321781375 |
10 | 26285070201107 |
11 | 8414487972913 |
12 | 2b462809b15ab |
13 | 11888963355b3 |
14 | 66c2c040020b |
15 | 308b05933722 |
hex | 17e7f845b113 |
26285070201107 has 2 divisors, whose sum is σ = 26285070201108. Its totient is φ = 26285070201106.
The previous prime is 26285070201101. The next prime is 26285070201109. The reversal of 26285070201107 is 70110207058262.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26285070201107 - 212 = 26285070197011 is a prime.
Together with 26285070201109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (26285070201101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13142535100553 + 13142535100554.
It is an arithmetic number, because the mean of its divisors is an integer number (13142535100554).
Almost surely, 226285070201107 is an apocalyptic number.
26285070201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
26285070201107 is an equidigital number, since it uses as much as digits as its factorization.
26285070201107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 94080, while the sum is 41.
Adding to 26285070201107 its reverse (70110207058262), we get a palindrome (96395277259369).
The spelling of 26285070201107 in words is "twenty-six trillion, two hundred eighty-five billion, seventy million, two hundred one thousand, one hundred seven".
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