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263314666413397 is a prime number
BaseRepresentation
bin111011110111101110111001…
…001001111101110101010101
31021112022122011211122212122001
4323313232321021331311111
5234003121414100212042
62332005030544435301
7106314566621145514
oct7367567111756525
91245278154585561
10263314666413397
117699a139655935
1225648191018b31
13b3c060ab87791
1449046d818267b
152069643413bb7
hexef7bb927dd55

263314666413397 has 2 divisors, whose sum is σ = 263314666413398. Its totient is φ = 263314666413396.

The previous prime is 263314666413349. The next prime is 263314666413427. The reversal of 263314666413397 is 793314666413362.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136081883791396 + 127232782622001 = 11665414^2 + 11279751^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-263314666413397 is a prime.

It is a super-2 number, since 2×2633146664133972 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (263314666413497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 131657333206698 + 131657333206699.

It is an arithmetic number, because the mean of its divisors is an integer number (131657333206699).

Almost surely, 2263314666413397 is an apocalyptic number.

It is an amenable number.

263314666413397 is a deficient number, since it is larger than the sum of its proper divisors (1).

263314666413397 is an equidigital number, since it uses as much as digits as its factorization.

263314666413397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 211631616, while the sum is 64.

The spelling of 263314666413397 in words is "two hundred sixty-three trillion, three hundred fourteen billion, six hundred sixty-six million, four hundred thirteen thousand, three hundred ninety-seven".