Base | Representation |
---|---|
bin | 100110010110010110101… |
… | …001011100111100111111 |
3 | 100022221021112122220201211 |
4 | 212112112221130330333 |
5 | 321134140123320333 |
6 | 5334354245345251 |
7 | 361253145545041 |
oct | 46262651347477 |
9 | 10287245586654 |
10 | 2635342401343 |
11 | 92670809a633 |
12 | 3668b6a08227 |
13 | 16168633aba2 |
14 | 917a08cda91 |
15 | 488409b2ecd |
hex | 26596a5cf3f |
2635342401343 has 2 divisors, whose sum is σ = 2635342401344. Its totient is φ = 2635342401342.
The previous prime is 2635342401311. The next prime is 2635342401401. The reversal of 2635342401343 is 3431042435362.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2635342401343 - 25 = 2635342401311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2635342401296 and 2635342401305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2635342441343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1317671200671 + 1317671200672.
It is an arithmetic number, because the mean of its divisors is an integer number (1317671200672).
Almost surely, 22635342401343 is an apocalyptic number.
2635342401343 is a deficient number, since it is larger than the sum of its proper divisors (1).
2635342401343 is an equidigital number, since it uses as much as digits as its factorization.
2635342401343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 40.
The spelling of 2635342401343 in words is "two trillion, six hundred thirty-five billion, three hundred forty-two million, four hundred one thousand, three hundred forty-three".
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