Base | Representation |
---|---|
bin | 11000100101101101… |
… | …110100001111011111 |
3 | 2112011001002120211120 |
4 | 120211231310033133 |
5 | 413033024234411 |
6 | 20043522422023 |
7 | 1623165103221 |
oct | 304555641737 |
9 | 75131076746 |
10 | 26402571231 |
11 | 10219621603 |
12 | 514a201913 |
13 | 2649ca541a |
14 | 13c6768411 |
15 | a47dc4106 |
hex | 625b743df |
26402571231 has 8 divisors (see below), whose sum is σ = 35204983344. Its totient is φ = 17600936640.
The previous prime is 26402571227. The next prime is 26402571241. The reversal of 26402571231 is 13217520462.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 26402571231 - 22 = 26402571227 is a prime.
It is a super-2 number, since 2×264025712312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 26402571192 and 26402571201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (26402571211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109900 + ... + 254721.
It is an arithmetic number, because the mean of its divisors is an integer number (4400622918).
Almost surely, 226402571231 is an apocalyptic number.
26402571231 is a deficient number, since it is larger than the sum of its proper divisors (8802412113).
26402571231 is a wasteful number, since it uses less digits than its factorization.
26402571231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 388761.
The product of its (nonzero) digits is 20160, while the sum is 33.
The spelling of 26402571231 in words is "twenty-six billion, four hundred two million, five hundred seventy-one thousand, two hundred thirty-one".
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