Base | Representation |
---|---|
bin | 11000100110001110… |
… | …011110001101000001 |
3 | 2112011122012111121110 |
4 | 120212032132031001 |
5 | 413042222203323 |
6 | 20044430113533 |
7 | 1623330626001 |
oct | 304616361501 |
9 | 75148174543 |
10 | 26411131713 |
11 | 1022343918a |
12 | 515104b8a9 |
13 | 264b9b19b5 |
14 | 13c7956001 |
15 | a48a15793 |
hex | 62639e341 |
26411131713 has 4 divisors (see below), whose sum is σ = 35214842288. Its totient is φ = 17607421140.
The previous prime is 26411131627. The next prime is 26411131723. The reversal of 26411131713 is 31713111462.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 26411131713 - 213 = 26411123521 is a prime.
It is a super-2 number, since 2×264111317132 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (26411131723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4401855283 + ... + 4401855288.
It is an arithmetic number, because the mean of its divisors is an integer number (8803710572).
Almost surely, 226411131713 is an apocalyptic number.
It is an amenable number.
26411131713 is a deficient number, since it is larger than the sum of its proper divisors (8803710575).
26411131713 is an equidigital number, since it uses as much as digits as its factorization.
26411131713 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8803710574.
The product of its digits is 3024, while the sum is 30.
The spelling of 26411131713 in words is "twenty-six billion, four hundred eleven million, one hundred thirty-one thousand, seven hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •