Base | Representation |
---|---|
bin | 100110011100001110001… |
… | …101100001000000011011 |
3 | 100100112112122221022001000 |
4 | 212130032031201000123 |
5 | 321240041141424011 |
6 | 5341315412000043 |
7 | 361565245442316 |
oct | 46341615410033 |
9 | 10315478838030 |
10 | 2641643311131 |
11 | 9293508663a0 |
12 | 367b75000023 |
13 | 16214b862886 |
14 | 91bdb66b97d |
15 | 48aadc39356 |
hex | 2670e36101b |
2641643311131 has 32 divisors (see below), whose sum is σ = 4273831238400. Its totient is φ = 1599305178240.
The previous prime is 2641643311127. The next prime is 2641643311133. The reversal of 2641643311131 is 1311133461462.
2641643311131 is a `hidden beast` number, since 2 + 6 + 4 + 1 + 643 + 3 + 1 + 1 + 1 + 3 + 1 = 666.
It is not a de Polignac number, because 2641643311131 - 22 = 2641643311127 is a prime.
It is a super-2 number, since 2×26416433111312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2641643311133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4414846 + ... + 4977363.
It is an arithmetic number, because the mean of its divisors is an integer number (133557226200).
Almost surely, 22641643311131 is an apocalyptic number.
2641643311131 is a deficient number, since it is larger than the sum of its proper divisors (1632187927269).
2641643311131 is a wasteful number, since it uses less digits than its factorization.
2641643311131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9393176 (or 9393170 counting only the distinct ones).
The product of its digits is 31104, while the sum is 36.
Adding to 2641643311131 its reverse (1311133461462), we get a palindrome (3952776772593).
The spelling of 2641643311131 in words is "two trillion, six hundred forty-one billion, six hundred forty-three million, three hundred eleven thousand, one hundred thirty-one".
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