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2642055850457 is a prime number
BaseRepresentation
bin100110011100100110110…
…011001110100111011001
3100100120121102012110121022
4212130212303032213121
5321241412244203312
65341424350052225
7361611415121012
oct46344663164731
910316542173538
102642055850457
11929542716291
1236806b1aa075
131621b617479a
1491c3a378009
1548ad5078172
hex26726cce9d9

2642055850457 has 2 divisors, whose sum is σ = 2642055850458. Its totient is φ = 2642055850456.

The previous prime is 2642055850453. The next prime is 2642055850487. The reversal of 2642055850457 is 7540585502462.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2348789195776 + 293266654681 = 1532576^2 + 541541^2 .

It is a cyclic number.

It is not a de Polignac number, because 2642055850457 - 22 = 2642055850453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2642055850399 and 2642055850408.

It is not a weakly prime, because it can be changed into another prime (2642055850453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1321027925228 + 1321027925229.

It is an arithmetic number, because the mean of its divisors is an integer number (1321027925229).

Almost surely, 22642055850457 is an apocalyptic number.

It is an amenable number.

2642055850457 is a deficient number, since it is larger than the sum of its proper divisors (1).

2642055850457 is an equidigital number, since it uses as much as digits as its factorization.

2642055850457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440000, while the sum is 53.

The spelling of 2642055850457 in words is "two trillion, six hundred forty-two billion, fifty-five million, eight hundred fifty thousand, four hundred fifty-seven".